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simple ques.

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Post by jyotsana Mon Oct 13, 2008 6:05 pm

A:- d relation 4 disp. covered in n^th sec. by a
uniformly acc. particle -
s = u + a/2[2n-1] is dimensinaly corect.

R:- 1 sec. is coeficient of both terms on RHS.
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Post by Infinity squared Mon Oct 13, 2008 6:41 pm

shud be (1)

check out last yrs AIATS paper 4 this chap Laughing
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Post by rt_08 Mon Oct 13, 2008 8:51 pm

hey i could nt understand the question
i just sought out and say that s=u+1/2a(2t-1) is dimensionally incorrect

rofl
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Post by jyotsana Tue Oct 14, 2008 10:59 am

i hv taken d ques frm dere only.
temme hw dis equation cn b dim. crect???

i'm nt satisfied so put d ques here
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Post by Infinity squared Tue Oct 14, 2008 11:15 am

well it was a MCQ there and not AR Razz

well try to derive it
and u'll find y it seems dim incorrect
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Post by jyotsana Tue Oct 14, 2008 11:34 am

i kno dat it ws MCQ .i jst converted it.
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Post by Infinity squared Tue Oct 14, 2008 11:37 am

understood?? fool
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Post by jyotsana Tue Oct 14, 2008 11:42 am

wel !tryin 2 understand dese silly things
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Post by rt_08 Tue Oct 14, 2008 12:34 pm

these are not silly things ,these clear our concepts(especially!!!!!!!!!!!!mine)
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Post by Infinity squared Tue Oct 14, 2008 10:23 pm

u can check out solutions--its clearly specified..

neways easier method...u can multiply both LHS and RHS by "t"
and then put t=1 in LHS (since we r taking of nth sec)
that wud make it dim correct...
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Post by Kayg_25 Sun Nov 23, 2008 7:14 pm

The answer is (1) acc. to me b/c on the rhs,both the terms give the dimensions of displacement if we multiply them by 1sec- u x t(=1) and a t(squared) (t=1) so....its dimentionally correct... It is for the nth sectond so t=1...it is similar to s=ut+1/2 at(squared)

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