Prove

now do tell me this:
prove:
product of any r consecutive natural no.s is divisible by r!

let r=6;
so the nos=1,2,3,4,5,6;
and i think 1*2*3*4*5*6 is divisible by 6
ha ha a fools solution


sorry arnav

maths in PMT???

y?
maths in pmt?

hey im srry for pmt...........
but i need a soltn i am serious
pl proove........its just eating my head away........
i kno its simple but still pl help

alrigth no need now i solvd it.myself...........

I triesd but couldn't prove

All i cud prove was that using PhP,we can put all r consecutive nos in 1 to 1 correspondance with digits in r!

it is going to yield me 2 out of 15 in RMO


Plz prove(or at-least give outline)

well i had to prove it by mathematical induction..........

if u still want d proof then tell............

well ya i wanted to ask wats d date of rmo.........
ive not yet filld the form..........
hope to get it tommorrow...........
in the worst case.........
in the best ill lyk the date to have passed...........

well can we proove wid mathematical induction........in rmo.......

why not

they acept all possible ways to prove

I also got the proof(by mathematical induction)
i was stupid in thinking it as combinatorics problem

but how combinatorics????????????
i thought induction was much better!

thats me,the stupid one

thats y i made this question too complex

date of rmo????????

well d quest can also b solvd wid d help of p&c

or probably binomial..........

nCr = n!/r!(n-r)!
=(n-1)n(n-2)(n-3).........(n-r+1)(n-r)!/r!(n-r)!
=n(n-1).......(n-r+1)/r!
=an integer coz nCr belongs to Z

hence
r!|product of r consecutiv integrs

thats simple!
well the date of rmo is 9 november
hey can u help me with HORNER'S METHOD OF SYNTHETIC DIVISION